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61 lines (52 loc) · 1.24 KB
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import java.util.Arrays;
import java.util.OptionalInt;
//21) How do you find second largest element in an array of integers?
//https://javaconceptoftheday.com/java-array-interview-questions-and-answers/
/**
*
* @author rishiraj
*
*/
public class SecondLargest {
public static void main(String[] args) {
int [] a = {3333,44,55,676,33,22,55};
// System.out.println("Second largest: " + sLargest(a));
System.out.println("Second largest: " + sLargestJ8(a));
// System.out.println(Arrays.toString(a));
}
//with Stream as in Java 8 and later
static int sLargestJ8(int[] a) {
int invalidSentinel = -1111111111;
final int max;
OptionalInt maxOpt = Arrays.stream(a).max();
if(maxOpt.isEmpty())
return invalidSentinel;
else
max = maxOpt.getAsInt();
maxOpt = Arrays.stream(a)
.filter(i -> i < max)
.max();
if(maxOpt.isEmpty())
return invalidSentinel;
else
return maxOpt.getAsInt();
}
static int sLargest(int[] a) {
int sl= -10000000;
int[] b = a.clone();
Arrays.sort(b);
int largest = largest(b);
for(int i: a) {
if(i == largest) continue;
if(i>sl) sl=i;
}
return sl;
}
static int largest(int[] b ) {
int l = -100000000;
for(int i : b) {
if(i>l) l = i;
}
return l;
}
}